Username: Save?
Password:
Home Forum Links Search Login Register*
    News: Welcome to the TechnoWorldInc! Community!
Recent Updates
[March 06, 2024, 02:45:27 PM]

[March 06, 2024, 02:45:27 PM]

[March 06, 2024, 02:45:27 PM]

[March 06, 2024, 02:45:27 PM]

[February 14, 2024, 02:00:39 PM]

[February 14, 2024, 02:00:39 PM]

[February 14, 2024, 02:00:39 PM]

[February 14, 2024, 02:00:39 PM]

[February 08, 2024, 10:26:18 AM]

[February 08, 2024, 10:26:18 AM]

[February 08, 2024, 10:26:18 AM]

[February 08, 2024, 10:26:18 AM]

[November 27, 2023, 06:32:12 PM]
Subscriptions
Get Latest Tech Updates For Free!
Resources
   Travelikers
   Funistan
   PrettyGalz
   Techlap
   FreeThemes
   Videsta
   Glamistan
   BachatMela
   GlamGalz
   Techzug
   Vidsage
   Funzug
   WorldHostInc
   Funfani
   FilmyMama
   Uploaded.Tech
   MegaPixelShop
   Netens
   Funotic
   FreeJobsInc
   FilesPark
Participate in the fastest growing Technical Encyclopedia! This website is 100% Free. Please register or login using the login box above if you have already registered. You will need to be logged in to reply, make new topics and to access all the areas. Registration is free! Click Here To Register.
+ Techno World Inc - The Best Technical Encyclopedia Online! » Forum » THE TECHNO CLUB [ TECHNOWORLDINC.COM ] » Career/ Jobs Zone » Placement Papers » Dharama Systems
 Technical - C Section
Pages: [1]   Go Down
  Print  
Author Topic: Technical - C Section  (Read 3023 times)
Tanya
TWI Addict
********



Karma: 1
Offline Offline

Posts: 4190


View Profile
Technical - C Section
« Posted: June 08, 2007, 02:00:14 AM »


Technical - C Section


 Give the output of the programs in each case unless mentioned otherwise

1.
void main()
{
int d=5;
printf("%f",d);
}

Ans: Undefined


2.
void main()
{
int i;
for(i=1;i<4,i++)
switch(i)
case 1: printf("%d",i);break;
{
case 2:printf("%d",i);break;
case 3:printf("%d",i);break;
}
switch(i) case 4:printf("%d",i);
}

Ans: 1,2,3,4


3.
void main()
{
char *s="12345sn";
printf("%d",sizeof(s));
}

Ans: 6


4.
void main()
{
unsigned i=1; /* unsigned char k= -1 => k=255; */
signed j=-1; /* char k= -1 => k=65535 */
/* unsigned or signed int k= -1 =>k=65535 */
if(i<j)
printf("less");
else
if(i>j)
printf("greater");
else
if(i==j)
printf("equal");
}

Ans: less


5.
void main()
{
float j;
j=1000*1000;
printf("%f",j);
}

1. 1000000
2. Overflow
3. Error
4. None

Ans: 4


6. How do you declare an array of N pointers to functions returning
pointers to functions returning pointers to characters?

Ans: The first part of this question can be answered in at least
three ways:

1. char *(*(*a[N])())();

2. Build the declaration up incrementally, using typedefs:

typedef char *pc; /* pointer to char */
typedef pc fpc(); /* function returning pointer to char */
typedef fpc *pfpc; /* pointer to above */
typedef pfpc fpfpc(); /* function returning... */
typedef fpfpc *pfpfpc; /* pointer to... */
pfpfpc a[N]; /* array of... */

3. Use the cdecl program, which turns English into C and vice
versa:

cdecl> declare a as array of pointer to function returning
pointer to function returning pointer to char
char *(*(*a)())()

cdecl can also explain complicated declarations, help with
casts, and indicate which set of parentheses the arguments
go in (for complicated function definitions, like the one
above).
Any good book on C should explain how to read these complicated
C declarations "inside out" to understand them ("declaration
mimics use").
The pointer-to-function declarations in the examples above have
not included parameter type information. When the parameters
have complicated types, declarations can *really* get messy.
(Modern versions of cdecl can help here, too.)


7. A structure pointer is defined of the type time . With 3 fields min,sec hours having pointers to intergers.
Write the way to initialize the 2nd element to 10.


8. In the above question an array of pointers is declared.
Write the statement to initialize the 3rd element of the 2 element to 10;


9.
int f()
void main()
{
f(1);
f(1,2);
f(1,2,3);
}
f(int i,int j,int k)
{
printf("%d %d %d",i,j,k);
}

What are the number of syntax errors in the above?

Ans: None.


10.
void main()
{
int i=7;
printf("%d",i++*i++);
}

Ans: 56


11.
#define one 0
#ifdef one
printf("one is defined ");
#ifndef one
printf("one is not defined ");

Ans: "one is defined"


12.
void main()
{
int count=10,*temp,sum=0;
temp=&count;
*temp=20;
temp=&sum;
*temp=count;
printf("%d %d %d ",count,*temp,sum);
}

Ans: 20 20 20


13. There was question in c working only on unix machine with pattern matching.


14. what is alloca()

Ans : It allocates and frees memory after use/after getting out of scope


15.
main()
{
static i=3;
printf("%d",i--);
return i>0 ? main():0;
}

Ans: 321


16.
char *foo()
{
char result[100]);
strcpy(result,"anything is good");
return(result);
}
void main()
{
char *j;
j=foo()
printf("%s",j);
}

Ans: anything is good.


17.
void main()
{
char *s={ "dharma","hewlett-packard","siemens","ibm"};
char **p;
p=s;
printf("%s",++*p);
printf("%s",*p++);
printf("%s",++*p);
}

Ans: "harma" (p->add(dharma) && (*p)->harma)
"harma" (after printing, p->add(hewlett-packard) &&(*p)->harma)
"ewlett-packard"

Logged

Pages: [1]   Go Up
  Print  
 
Jump to:  

Copyright © 2006-2023 TechnoWorldInc.com. All Rights Reserved. Privacy Policy | Disclaimer
Page created in 0.058 seconds with 25 queries.